UISearchBar cancel button color?

When I drop a UISearchBar into my view inside Interface Builder, and change its style to Black Opaque, the cancel button stays unfittingly blue / gray and doesn't become black.

How can I make the cancel button black?

EDIT: It does work like this:

// Assume a UISearchBar searchBar.
NSArray *subviews = [searchBar subviews];

// The index depends on how you configure the searchBar.
UIButton *cancelButton = [subviews objectAtIndex:3];

// Set the style to "normal" style.
[cancelButton setStyle:0];

But the setStyle: method is from a private framework, so this might be an issue when submitting the app to Apple.

Answers


I used some thing like this and worked with me:

[[UIBarButtonItem appearanceWhenContainedIn: [UISearchBar class], nil] setTintColor:[UIColor blackColor]];

it changed the cancel button color to black.

Update for iOS 9.0, the method appearanceWhenContainedIn is deprecated, use appearanceWhenContainedInInstancesOfClasses instead:

[[UIBarButtonItem appearanceWhenContainedInInstancesOfClasses:@[[UISearchBar class]]] setTintColor:[UIColor blackColor]];

And in Swift 3:

UIBarButtonItem.appearance(whenContainedInInstancesOf:[UISearchBar.self]).tintColor = UIColor.black

The problem with your solution is that the code is assuming that the objectAtIndex:3 is the cancel button. Not only does this generate a compiler warning, but also if you are displaying the Cancel button programmatically (for example using [searchBar setShowsCancelButton:YES], you risk crashing the application.

A simpler solution is to set the style of the whole search bar in ViewDidLoad(), using:

searchBar.tintColor = [UIColor colorWithWhite:0.3 alpha:1.0];

this overrides the style set in the Interface Builder BUT also changes the colour of the Cancel button to be same colour as the whole bar (although it doesn't let you set the style of Cancel button independently, unfortunately.


Try this and see: (I tested below code with Swift 4.1 - Xcode 9.3-beta4)

@IBOutlet weak var sbSearchBar: UISearchBar!

sbSearchBar.tintColor = UIColor.red
sbSearchBar.showsCancelButton = true
sbSearchBar.barTintColor = UIColor.blue
sbSearchBar.tintColor = UIColor.red

if let buttonItem = sbSearchBar.subviews.first?.subviews.last as? UIButton {
    buttonItem.setTitleColor(UIColor.yellow, for: .normal)
}


This is an updated version of Hossam Ghareeb's answer above for Swift 3:

UIBarButtonItem.appearance(whenContainedInInstancesOf: [UISearchBar.self] ).tintColor = UIColor.red

But this will not override appearance if it has already been set elsewhere for UIBarButtonItem.

For example, in my navbar controller I had to change this:

UIBarButtonItem.appearance().setTitleTextAttributes([NSForegroundColorAttributeName:UIColor.white], for: UIControlState.normal)

To this for the solution above to work:

UIBarButtonItem.appearance(whenContainedInInstancesOf: [UINavigationBar.self] ).setTitleTextAttributes([NSForegroundColorAttributeName:UIColor.white], for: UIControlState.normal)

In Swift 4.2

let appearance = UIBarButtonItem.appearance(whenContainedInInstancesOf: [UISearchBar.self])
appearance.setTitleTextAttributes([NSAttributedString.Key.foregroundColor: UIColor(named: "goldColor")!], for: .normal)

This works for me. Thanks @Tim Semple


for iOS 10:

UISearchBar.appearance().tintColor = UIColor.red //cancel button color
UISearchBar.appearance().barTintColor = UIColor.blue //background button color

I have taken Benjamin's answer and combined it with safe Array lookup to produce a short, but safe functional version:

searchController.searchBar.tintColor = UIColor.whiteColor()
(searchController.searchBar.subviews[safe: 0]?.subviews as? [UIView])?
    .filter({$0.isKindOfClass(UITextField)})
    .map({$0.tintColor = .lightGrayColor()})

This results in coloring the Cancel button white and the cursor when typing gray. Otherwise it would be white and thus not seen. The searchController is an object of type UISearchController. If anybody wants to use it inside the results controller, replace it with self.

The implementation of the safe: subscript is nkukushkin's answer:

extension Array {
    subscript(safe index: Int) -> T? {
        return indices(self) ~= index ? self[index] : nil
    }
}

Click on Search bar and set the tint color under view from Interface Builder.


let view: UIView = self.searchBar.subviews[0] as UIView
let subViewsArray = view.subviews

for subView: UIView in subViewsArray {
    if let cancelButt = subView as? UIButton{
        cancelButt.setTitleColor(UIColor.white, for: .normal)         
    }
}

This worked for me


For those looking to reproduce the same behavior in Swift :

override func viewWillAppear(animated: Bool) {
    self.searchBar.tintColor = UIColor.whiteColor()

    let view: UIView = self.searchBar.subviews[0] as! UIView
    let subViewsArray = view.subviews

    for (subView: UIView) in subViewsArray as! [UIView] {
        println(subView)
        if subView.isKindOfClass(UITextField){
            subView.tintColor = UIColor.blueColor()
        }
    }

}

Need Your Help

Access props inside quotes in React JSX

javascript reactjs react-props

In JSX, how do you reference a value from props from inside a quoted attribute value?